Question

calculate maximum horizontal distance travelled by a ball thrown with velocity of 40 m/s without hitting the ceiling of an auditorium of height 25 m​

Answer 1

Given,

Hight of Hall( H) = 25 m

Let ball is thrown with speed 40m/s at an angle ∅ with horizontal .

We know,

H = u²sin²∅/2g

25= (40)² × sin²∅/2× 10

25 = 80 × sin²∅

Sin²∅ = 25/80

Sin∅ = 5/4√5

Cos∅ = √55/4√5

Now, horizontal range = u²sin2∅/g

= (40)²× 2sin∅×cos∅/g

= 160 × 2 × 5/4√5 × √55/4√5

= 20√55 m

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