calculate mean CB :0-4, 5-9, 10-14, 15-19, 20-24 use all the method
Answers
Answer:
Answer:mean 12.2
Answer:mean 12.2median 12
Answer:mean 12.2median 12modal class 10-14 or mode 12 (whichever is done in class)
Answer:mean 12.2median 12modal class 10-14 or mode 12 (whichever is done in class)Step-by-step explanation:
Answer:mean 12.2median 12modal class 10-14 or mode 12 (whichever is done in class)Step-by-step explanation:Treat the values as though there were simply all the middle value in the respective classes. The central values are 2 (for the class 0-4), 7 (for the class 5-9), 12, 17 and 22.
Answer:mean 12.2median 12modal class 10-14 or mode 12 (whichever is done in class)Step-by-step explanation:Treat the values as though there were simply all the middle value in the respective classes. The central values are 2 (for the class 0-4), 7 (for the class 5-9), 12, 17 and 22.So the for the mean, we have
Answer:mean 12.2median 12modal class 10-14 or mode 12 (whichever is done in class)Step-by-step explanation:Treat the values as though there were simply all the middle value in the respective classes. The central values are 2 (for the class 0-4), 7 (for the class 5-9), 12, 17 and 22.So the for the mean, we havemean = ( sum of value times frequency ) / ( sum of frequencies )
Answer:mean 12.2median 12modal class 10-14 or mode 12 (whichever is done in class)Step-by-step explanation:Treat the values as though there were simply all the middle value in the respective classes. The central values are 2 (for the class 0-4), 7 (for the class 5-9), 12, 17 and 22.So the for the mean, we havemean = ( sum of value times frequency ) / ( sum of frequencies )= ( 2×2 + 7 × 6 + 12 × 10 + 17 × 5 + 22 × 3 ) / ( 2 + 6 + 10 + 5 + 3)
Answer:mean 12.2median 12modal class 10-14 or mode 12 (whichever is done in class)Step-by-step explanation:Treat the values as though there were simply all the middle value in the respective classes. The central values are 2 (for the class 0-4), 7 (for the class 5-9), 12, 17 and 22.So the for the mean, we havemean = ( sum of value times frequency ) / ( sum of frequencies )= ( 2×2 + 7 × 6 + 12 × 10 + 17 × 5 + 22 × 3 ) / ( 2 + 6 + 10 + 5 + 3)= 317 / 26
Answer:mean 12.2median 12modal class 10-14 or mode 12 (whichever is done in class)Step-by-step explanation:Treat the values as though there were simply all the middle value in the respective classes. The central values are 2 (for the class 0-4), 7 (for the class 5-9), 12, 17 and 22.So the for the mean, we havemean = ( sum of value times frequency ) / ( sum of frequencies )= ( 2×2 + 7 × 6 + 12 × 10 + 17 × 5 + 22 × 3 ) / ( 2 + 6 + 10 + 5 + 3)= 317 / 26≈ 12.2
Answer:mean 12.2median 12modal class 10-14 or mode 12 (whichever is done in class)Step-by-step explanation:Treat the values as though there were simply all the middle value in the respective classes. The central values are 2 (for the class 0-4), 7 (for the class 5-9), 12, 17 and 22.So the for the mean, we havemean = ( sum of value times frequency ) / ( sum of frequencies )= ( 2×2 + 7 × 6 + 12 × 10 + 17 × 5 + 22 × 3 ) / ( 2 + 6 + 10 + 5 + 3)= 317 / 26≈ 12.2For the median, we need to indentify the "middle". There are 2 + 6 + 10 + 5 + 3 = 26 values. Being even, there are two central values, and these are the 13th and 14th values (used 13 = 26 / 2). From the frequencies 2, 6, 10, 5, 3, the cumulative frequencies are 2, 8, 18, 23, 26. So once we've looked at the first class, we've looked at 2 values; after looking over the second class, we've passed by 8 values (we're looking for the 13th and 14th, so we're not there yet); after the third class, we've passes over 18 values ... that's it, we passed the 13th and 14th values --- they are in the third class and so are treated as value 12. For the median, we take the average of these two values, which is just 12. (This last step would matter if one were in one class and the other in the next class.)
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