Math, asked by ramyasada, 1 month ago

Calculate Median for
the following
x - 17, 32 , 35, 32,15 21,42,11,12,18​

Answers

Answered by mayajakhar79
5

Solution:-

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\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}

⇝ Here, the data has been given to us in the question that is 17, 32, 35, 32, 15, 21, 42, 11, 12, 18. Now, the question has asked us to find out the median of the given data.

HOW TO DO:-

  • To find the median we will apply the formula of median. Arrange the data in ascending or descending order. There are 10 terms in the data. If the number of terms is even then we will apply (n/2) + 1th formula.

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ANSWER:-

» The median is 21.

GIVEN:-

✪ Data = 17, 32, 35, 32, 15, 21, 42, 11, 12, 18

TO FIND:-

  • Here we have to find the median of the given data.

SOLVING STEP BY STEP:-

  • We simply need to apply the formula.
  • First of all solve the bracket.
  • Then add 1 to the quotient.
  • The final digits will be the answer.

We know that:-

 \purple{\bigstar} \:  \underline{\boxed{ \rm \pink{{Median =  \left(\dfrac{N}{2} \right) + 1\: term}}}}

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So let's solve it!

  • Finding the median:-

✪ Data = 17, 32, 35, 32, 15, 21, 42, 11, 12, 18

⟶ Arrange in ascending = 11, 12, 15, 17, 18, 21, 32, 32, 35, 42

⟶ No. of terms in data = 10 terms

⟶ N = 10

\to{\sf Median =  \left(\dfrac{10}{2} \right)+ 1 \: term}

\to{\sf Median =  \left(\dfrac{ \not1 \!\!\!\not0}{ \not2} \right)+ 1 \: term}

\to{\sf Median =  \left(\dfrac{5}{1} \right)+ 1 \: term}

\to{\sf Median =  5 + 1 \: term}

\to{\sf Median =  5 + 1th = 6 \: term}

 \orange{\ast} \: \overline{\boxed{\tt \pink{Median = 6 \: term}}}

⟶ Median = 6th term

⟶ Median = 21 [As 21 is the 6th term]

Thus, we got the median. The 6th term that is 21. is the median of the data.

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KNOW MORE:-

  • The formula used above is used when data is not given in form of a table.
  • The Formula of median when the data is given in tables or frequencies.
  • If n is odd then (n+1)/2th term will be median.
  • If n is even then average of middle two terms which are n/2th term and (n/2)+1th term is median.

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Answered by muskanshi536
2

Step-by-step explanation:

Solution:-

━━━━━━━━━━━━━━━━━━━━━━━━━━

\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}

⇝ Here, the data has been given to us in the question that is 17, 32, 35, 32, 15, 21, 42, 11, 12, 18. Now, the question has asked us to find out the median of the given data.

✺ HOW TO DO:-

To find the median we will apply the formula of median. Arrange the data in ascending or descending order. There are 10 terms in the data. If the number of terms is even then we will apply (n/2) + 1th formula.

----------------------

ANSWER:-

» The median is 21.

GIVEN:-

✪ Data = 17, 32, 35, 32, 15, 21, 42, 11, 12, 18

TO FIND:-

Here we have to find the median of the given data.

SOLVING STEP BY STEP:-

We simply need to apply the formula.

First of all solve the bracket.

Then add 1 to the quotient.

The final digits will be the answer.

We know that:-

 \purple{\bigstar} \:  \underline{\boxed{ \rm \pink{{Median =  \left(\dfrac{N}{2} \right) + 1\: term}}}}

----------------------

So let's solve it!

Finding the median:-

✪ Data = 17, 32, 35, 32, 15, 21, 42, 11, 12, 18

⟶ Arrange in ascending = 11, 12, 15, 17, 18, 21, 32, 32, 35, 42

⟶ No. of terms in data = 10 terms

⟶ N = 10

\to{\sf Median =  \left(\dfrac{10}{2} \right)+ 1 \: term}

\to{\sf Median =  \left(\dfrac{ \not1 \!\!\!\not0}{ \not2} \right)+ 1 \: term}

\to{\sf Median =  \left(\dfrac{5}{1} \right)+ 1 \: term}

\to{\sf Median =  5 + 1 \: term}

\to{\sf Median =  5 + 1th = 6 \: term}

 \orange{\ast} \: \overline{\boxed{\tt \pink{Median = 6 \: term}}}

⟶ Median = 6th term

⟶ Median = 21 [As 21 is the 6th term]

Thus, we got the median. The 6th term that is 21. is the median of the data.

----------------------

KNOW MORE:-

The formula used above is used when data is not given in form of a table.

The Formula of median when the data is given in tables or frequencies.

If n is odd then (n+1)/2th term will be median.

If n is even then average of middle two terms which are n/2th term and (n/2)+1th term is median.

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