calculate MI of thin uniform rod of mass 20g and length 60cm about an axis perpendicular to its length and passing through, 1.its center 2.one end of rod
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Given-
Mass of rod=M=100g=0.1kg, length of rod=l=60cm=0.6m.
Moment of inertia of the thin uniform rod about a transverse axis passing through its centre is given by-
І=Ml2/12=0.1*(0.6)2/12=0.003kg m2
Moment of inertia of the thin uniform rod about a transverse axis passing through its end is given by-
І=Ml2/3=0.1*(0.6)2/3=0.012kg m2
Answer-Moment of inertia of the thin uniform rod about a transverse axis passing through its centre is 0.003kg m2 and the moment of inertia of the thin uniform rod about a transverse axis passing through its end is 0.012kg m2.
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