Question

calculate molality and mole fraction of solute in a following solution a sugar syrup of mass 214.2 gram containing 34.2 gram of sucrose​

Answer 1

Answer:

(i) The molal concentration is, 0.55 mole/Kg

(ii) Mole fraction of sugar in the syrup is,

Solution for part (i) :

Molality : It is defined as the number of moles of solute present in one kilogram of solvent.

Solute = sugar

Solution = sugar syrup

Solvent = water

First we have to calculate the mass of solvent.

Mass of solvent = Mass of sugar syrup - Mass of sugar = 214.2 - 34.2 = 180 g

Now we have to calculate the molality.

Therefore, the molal concentration is, 0.55 mole/Kg

Solution for part (ii) :

Now we have to calculate the moles of solute and solvent.

Now we have to calculate the mole fraction of sugar in the syrup.

Therefore, the mole fraction of sugar in syrup is,