Chemistry, asked by subramanyamreddysr65, 4 months ago

calculate molality of 10 g of glucose (C6 H12 o6) in 90 gm of water

Answers

Answered by piyushgupta2409

2

Explanation:

molar mass of glucose= 180g/mol

no of moles of glucose = 10/180 mol

mass of solvent =0.090 Kg

molality= no of moles of solute / mass of solvent in kg

molality = (10/180)/0.09

molality=0.617 m

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