Calculate molality of 10% NaOH by mass(w/w).
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Explanation:
10%NaOH means 10g of NaOH in 100g soln.
weight of solvent = weight of soln.- weight of solute
=100-10=90g
given mass of NaOH= 10g
Molar mass of NaOH=40g mol^-1
no. of moles of NaOH=
given mass/molar mass
=10/40
=2.5 mol
molality =
no.of moles of NaOH/wt of solvent(in kg)
=2.5*1000/90
=2500/90
=27.77m
I hope this ans might help u
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