Question

calculate molality of 10% urea by mass in water​

Answer 1

Answer

We have,

molality of urea solution = 10m

that means,

1000g of water contain urea = 10 moles = 10∗60=600g of urea

so, mass of solution = solute+solvent=1000+600=1600g

so, mass% =

massofsolution

massofsolute

∗100=

1600

600

∗100=37.5%

Answer 2

Answer:

Mass percentage(%) $= 37.5%$%

Explanation:

To find the mass rate(percentage)

As per the meaning of molality,

$1000g$ of water contains 10 moles of urea

10 moles of urea = 10× molar mass of urea

= 10×60

=600g of urea

The mass of the solute = 600g

The mass of arrangement(solution) = mass of solute + mass of dissolvable

= 600+1000

= 1600g

The mass rate(%) =  $\frac{mass of solute}{mass of solution} * 100$

⇒Mass rate(%) =  $\frac{600}{1600} *100$

We realize that molality is a proportion of the complete moles of a solute in one kilogram of a dissolvable.

Molality(m) =  $\frac{mass of dissolvable in Kg}{Number of moles of solvent}$

Here, thickness is optional as we now have the estimating factor which is the molar mass of urea. Consequently, the mass level of 10 moles of watery arrangement of urea is 37.5%

To learn more about Molality, visit

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