Chemistry, asked by blackpinkrose, 7 months ago

calculate molality of a 3 molar aqueous solution of NaCl whose density is 0.9g m /L​

Answers

Answered by hello78987
2

Answer:

hope this helps

Explanation:

Answer:

Explanation:

density=1.25

m=3 mol /lit

molar mass of nacl=58.5

weight=n* molecular weight

          =3*58.5

          =175.5g

mass=density*volume

             =1000*1.25

              =1250

mass of water in solution=1250-175.5

                                          =1074.5

molality=no.of moles/mass of solvent in kg

                 =3/1.07=2.8

Answered by rinkisingh46726
0

Answer:

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