Question

Calculate molality of ammonia in a solution containing 0.85g of nh3 in 100cm^3 of a liquid of density 0.85 gcm^-3

Answer 1

Answer:

molarity= 0.597

Explanation:

Density =0.85g/cm^3=8.5g/0.01L

=85g/0.1L

every 0.1 of that solution weights 85g

there are 85g of NH3 in 100 cm^3=0.85g/0.1L

mass of water in solution =85-0.85=84.15g=0.08415kg

No.of moles of NH3=0.85/17=0.05mol

Molality =0.05/0.08415=0.597