calculate molality of solution contains 5.3 gm of anhydrous SODIUM CARBONATE IN 400GM OF WATER
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Explanation:
5.3/106 => 0.05. Mass of the solvent => 400 g =>0.4 kg. Molality of the solution => Number of moles of solute/Mass of the solvent => 0.05/0.4 => 0.125 m.
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