Question

Calculate molality of solution of a substance dissolve in benzene having boiling point 353.71K. Given that Kb for benzene is 2.53K kgmole and boiling point of solution is 353.35k​

Answer 1

Given :

➳ BP of solvent = 353.71K

➳ BP of solution = 353.35K

➳ Kb of solvent = 2.53 K kg/mol

To Find :

⟶ Molality of the solution.

SoluTion :

➠ Formula of elevation of boiling point is given by

$\bigstar\:\underline{\boxed{\bf{\Delta T_b=K_b\times m}}}$

where,

▪ m is molality of solution

▪ Kb is called boiling point elevation constant

$\leadsto\sf\:(353.71-353.35)=2.53\times m$

$\leadsto\sf\:0.36=2.53\times m$

$\leadsto\boxed{\bf{m=0.14\:mol(kg)^{-1}}}$

Answer 2

hello i have given my best