Question

Calculate molality of solution when 250 g of glucose is dissolved in water to form 2.5 kg of its

aqueous solution.​

Answer 1

Answer:

Explanation:

Answer: The molality of the solution is 0.6172 mol/kg.

Answer 2

Given :

• Mass of glucose dissolved = 250g
• Mass of solution = 2.5 kg

To find :

Molality of Solution

Forumula used :

• Number of mole = mass ÷ molar mass
• Molality = Number of mole of Solute ÷ Mass of solvent ( in kg)

Solution :

First of all we need to find moles of glucose and mass of water.

Number of mole of glucose = 250g ÷ 180 g/mol

➝ Number of mole of glucose = 1.39 mol

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Mass of Solution = mass of solute + mass of solvent

➝ 2500 g = 250 g + mass of solvent

➝ mass of solvent = 2500g - 250g

➝ Mass of solvent = 2250 g

➝ Mass of solvent = 2.25 kg

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$\sf \: Molality \: = \: \dfrac{1.39 \: mol}{2.25 \: kg} \\ \\ \sf \implies \: Molality \: = \: 0.62m$

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ANSWER : 0.62m