Question

Calculate molar mass of Al2O3.K2O.6SiO3??with explanation

Answer 1

Answer:

Explanation:

Formula: K2O.Al2O3.6SiO3

Molar Mass: 652.648 g/mol        1g=1.53221951189615E-03 mol

Percent composition (by mass):

Element  Count           Atom Mass                %(by mass)

K                  2                  39.098                        11.98%

O                  22                15.999                        53.93%

Al                2                  26.982                        8.27%

Si                6                  28.085                        25.82%

Answer 2

The molar mass of $Al_2O_3.K_2O.6SiO_3$ is 556.64 g/mol.

We need to know the molar masses of all the components of the compound, as well as their relative ratios, in order to compute the molar mass of the given compound.

$Al_2O_3.K_2O.6SiO_3$  may be divided into three sections, each of which contains a distinct ingredient or combination of elements:

$Al_2O_3$ : This has 3 atoms of oxygen and 2 atoms of aluminium (Al) (O).

Al has a molar mass of 26.98 g/mol, while O has a molar mass of 16.00 g/mol. $Al_2O_3$ 's molar mass is as a result:

(2 x 26.98 g/mol) + (3 x 16.00 g/mol) = 101.96 g/mol

$K_2O$ : This molecule has 2 potassium (K) atoms and 1 oxygen atom (O).

K has a molar mass of 39.10 g/mol, while O has a molar mass of 16.00 g/mol.

As a result, $K_2O$ 's molar mass is:

(2 x 39.10 g/mol) + (1 x 16.00 g/mol)

= 94.20 g/mol

$6SiO_3$ : This contains 6 molecules of silica ($SiO_2$).

Si has a molar mass of 28.09 g/mol, while O has a molar mass of 16.00 g/mol.

As a result, the molar mass of $SiO_2$ is:

(1 x 28.09 g/mol) + (2 x 16.00 g/mol)

= 60.08 g/mol

Just multiplying the molar mass of $SiO_2$ by 6 will get the molar mass of $6SiO_3$:

6 x 60.08 g/mol = 360.48 g/mol

The molar masses of the three components may now be added up to determine the compound's overall molar mass:

101.96 g/mol + 94.20 g/mol + 360.48 g/mol = 556.64 g/mol

Hence, the molar mass of $Al_2O_3.K_2O.6SiO_3$ is 556.64 g/mol.

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