calculate molar volume of an ideal gas at 2 ATM and 300k
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Answer:
As given that :
Temperature (T)= 300k
Pressure (P)= 2 ATM
we know the ideal gas equation is given as-
PV = nRT
so V = nRT/P
V = 1× 0.082× 300 / 2. { • n = 1 }
V = 12.3 Ans.
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