Question

Calculate molarity & molality of 15% HNO3 solution (density = 1.5 g/cc).​

Answer 1

Answer:

$Density of nitric acid solution =1.04gmcm−3</p><p></p><p></p><p>Volume of 100gm solution =1.04100=96.15cm3=96.15×10−3dm3</p><p></p><p></p><p>Molarity =Molar mass of solute×Volume of solution in LMass of solute</p><p></p><p></p><p>              =63×96.15×10−36.3=1.04mol/L</p><p></p><p></p><p>6.3% HNO3 means 6.3g of HNO3 present in 100gm of solution</p><p></p><p></p><p>∴ Mass of water =100−6.3=93.7g</p><p></p><p></p><p>Molality of HNO3=Molar mass of HNO3×Mass of solvent(kg)Mass of HNO3</p><p></p><p></p><p>                                 =63×93.7×10−36.3</p><p></p><p></p><p>                                  =1.067 mol/Kg</p><p></p><p>$

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Answer 2

Answer:

6.3 is the correct answer