Calculate molarity & molality of 15% HNO3 solution (f = 1.5 g/cc).
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Answer:
=1.067 mol/Kg
Explanation:
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Density of nitric acid solution =1.04gmcm
−3
Volume of 100gm solution =
1.04
100
=96.15cm
3
=96.15×10
−3
dm
3
Molarity =
Molar mass of solute×Volume of solution in L
Mass of ssolut
=63×96.15×10-3
6.3
=1.04mol/L
6.3% HNO
3
means 6.3g of HNO
3
present in 100gm of solution
∴ Mass of water =100−6.3=93.7g
Molality of HNO
3
=
Molar mass of HNO
3
×Mass of solvent(kg)
Mass of HNO
3
=
63×93.7×10
−3
6.3
=1.067 mol/Kg
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