calculate molarity in .74g of Ca(OH)2 in 5ml of solution
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molarity is given as MOLES/LITER
normality is given as EQUIVALENTS/LITER
So, first figure out moles of Ca(OH)2; then liters of solution; then divide one by the other to get molarity.
moles Ca(OH)2 = 0.74 g x 1mol/74g = 0.01 moles
liters of solution = 15 ml x 1L/1000ml = 0.015L
Molarity = moles/liters = 0.01moles/0.015L = 0.007 molar
For normality, each mole of Ca(OH)2 yields TWO moles or TWO equivalents of OH-, so number of equivalents will be 2 x 0.01 = 0.02
normality = equivalents/liter = 0.02/0.015 = 1.33 normal
Thus, the normality is 2x (twice) the molarity because there are 2 equivalents for each mole.
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