calculate molarity of 100 ml of 0.2 Moler H2so4 with 50 ml of 0.1 Moler hcl
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Answer:
KNO
3
+
(400×0.2=80 mmol)
HCl
+
(500×0.3=150 mmol)
H
2
SO
4
Total volume =100+400+500=1000 mL
M
K
+
=
1000
10
=0.01 M
M
SO
4
−2
=
1000
150
=0.15 M
M
H
+
=
1000
80+2×150
=0.38 M
M
NO
3
−
=
1000
10
=0.01 M
M
Cl
−
=
1000
80
=0.08 M
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