Question

. Calculate Molarity of 100mL of solution containing 12.6g of Nitric acid

Answer 1

Answer:

Density of nitric acid solution =1.04gmcm

−3

Volume of 100gm solution =

1.04

100

=96.15cm

3

=96.15×10

−3

dm

3

Molarity =

Molar mass of solute×Volume of solution in L

Mass of solute

=

63×96.15×10

−3

6.3

=1.04mol/L

6.3% HNO

3

means 6.3g of HNO

3

present in 100gm of solution

∴ Mass of water =100−6.3=93.7g

Molality of HNO

3

=

Molar mass of HNO

3

×Mass of solvent(kg)

Mass of HNO

3

=

63×93.7×10

−3

6.3

=1.067 mol/Kg