calculate molarity of 3mol of Na2SO4.10H2O in 250ml water. Assume Volume due to solute negligible.
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1
given.
no of moles = 3
volume=0.25L
molarity= moles of solute/ volume of solution
= 3/0.25
=300/25
=12 molar
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Explanation:
water will also come from 10extra molecules of h20 that is present in na2so4 that is 3moles x 10molecules=30ml of extra water will be added to 250ml of water and in case we can consider volume of solvent=volume of soln...
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