Question

calculate molarity of 48.0ml of 6.00 M h2so4 diluted to 0.250 l 1.15M h2s04​

Answer 1

Answer:

The answer is

1.15

m

.

Since molality is defined as moles of solute divided by kg of solvent, we need to calculated the moles of

H

2

S

O

4

and the mass of the solvent, which I presume is water.

We can find the number of

H

2

S

O

4

moles by using its molarity

C

=

n

V

→

n

H

2

S

O

4

=

C

⋅

V

H

2

S

O

4

=

6.00

m

o

l

e

s

L

⋅

48.0

⋅

10

−

3

L

=

0.288

Since water has a density of

1.00

k

g

L

, the mass of solvent is

m

=

ρ

⋅

V

w

a

t

e

r

=

1.00

k

g

L

⋅

0.250

L

=

0.250

k

g

Therefore, molality is

m

=

n

m

a

s

s

.

s

o

l

v

e

n

t

=

0.288

m

o

l

e

s

0.250

k

g

=

1.15

m

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