Question

calculate molarity of 49% solution of H2SO4 having density 2.8 gml^-1​

Answer 1

Answer:

14.001 M

Explanation:

let solution mass=100g

it will have 49 g h2so4

using density=mass/volume

volume=100g/2.8=35.71 ml

moles of h2so4=49/98=0.5mole

Molarity=no of moles of solute/vol of solution in litre= 0.5*1000/35.71= 14.001M