Question

Calculate molarity of 9.8% (w/w) solution of H2SO4 if the density of the solution is 1.02g/ml?(molar mass of h2so4 is 98 gper mole
)

Answer 1

to solve it we found the answer is 1 02 M

Answer 2

Answer: The molarity of the solution is 1.02 M.

Explanation:

We are given:

9.8%(w/w) $H_2SO_4$ solution.

This that means 9.8 grams of $H_2SO_4$ is present in 100 gram of solution.

To calculate the molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of the solute}}{\text{Volume of the solution (in L)}}$    ....(1)

We are given:

Density of the solution = 1.02 g/mL

Molar mass of  $H_2SO_4$=98 g/mol

Mass of  $H_2SO_4$ = 9.8

Mass of solution = 100 grams

To calculate the volume of the solution, we use the equation:

$\text{Density}=\frac{Mass}{Volume}$

$1.02g/mL=\frac{100g}{\text{Volume of the solution}}\\\\\text{Volume of the solution}=98.03mL=0.098L$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Number of moles of solution}=\frac{9.8g}{98g/mol}=0.1mol$

Putting values in equation 1, we get:

$\text{Molarity of the solution}=\frac{0.1mol}{0.098L}=1.02mol/L$

Hence, the molarity of the solution is 1.02 M.