Question

calculate molarity of a aqueous solution of glocose in which 1.8 g of glucose present in 100 ml of solution​

Answer 1

Answer: 0.1M IS THE ANSWER.

Explanation:

MOLARITY=$\frac{WEIGHT}{GRAM MOLECULAR WEIGHT} X\frac{1000}{VOLUME (ml)}$

                  =1.8/180×1000/100=0.1M.

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