Chemistry, asked by BAAZ7466, 10 months ago

CALCULATE MOLARITY OF AN aq. SOLUTION OF UREA WHOSE VAPOUR PRESSURE IS REDUCED BY 25%.​

Answers

Answered by jonesofthequeens567
0

Answer:

Raoult's equation shows how to calculate the change in the vapor pressure of a solution from the vapor pressure of the pure solvent: Psolution = xsolventPsolvent, where Psolution is the resulting vapor pressure of the solution, xsolvent is the mole fraction of the solvent and Psolvent is the vapor pressure of the pure ...

Explanation:

Answered by Anonymous
1

Answer:

)

Given

Ps=(98100)P0

We know that

P0−PsPs=w×Mm×W

⇒wm×W×1000×M1000

Molality =w×1000m×W

∴P0−PsPs=molality ×M1000

∴P0−(98/100)P0(98/100)P0=molality ×100018

∴ Molality =2P0/10098100P0×100018

=1.133

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