Question

calculate molarity of solution containing 16 gm glucose per 300 ml soluton

Answer 1

Moles of glucose = Weight / GMW
= 16 / 18
= 8/9 mol

Molarity = Moles / Volume in litres
= (8/9) / (300 × 10^-3)
= 2.96 M

Molarity of solution is 2.96 M

Answer 2

Given:

Mass of solute (Glucose) = 16 g

Mass of the solution = 300ml

To find:

Molarity = ?

Formula to be used:

1. Number of moles = $\frac{Given mass}{Molar mass}$
2. Molarity = $\frac{Number of moles}{Volumes in Litres}$

Calculation:

As solute is given as glucose, the number of moles present in it must be calculated. The formula used is

Number of moles = $\frac{Given mass}{Molar mass}$ = $\frac{16}{180} = 0.08 moles$

As the volume is given in ml, it must be converted into L,

∴ 300ml = 0.3L

Thus substituting the given values in the following formula, it gives the molarity of the solution

Molarity = $\frac{Number of moles}{Volumes in Liters}$ = $\frac{0.08}{0.3} = 0.296$

Conclusion:

Thus the molarity of the solution is calculated as 0.296M

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