Question

calculate molarity of solution containing 16 gm glucose per 300 ml solution
lution

Answer 1

Given Data :-

16 gram of glucose

First of all find out moles of glucose

Moles of glucose = mass / molar mass

Molar mass of glucose = C6H12O6

Molar mass of glucose = 12 ×6 + 1×12 + 16×6

Molar mass of glucose = 180g/mol

Moles of glucose = 16 / 180

Moles of glucose = 0.088mol

Volume of solution = 300ml

Convert it into litre

Volume of solution = 0.3 litre

NOW

Molarity = moles of solute / volume of solution (in litre /dm^3)

Molarity = 0.088/0.3

Molarity = 0.293 M


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Answer 2

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Explanation:

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