calculate molarity of solution containing 16 gm glucose per 300 ml solution
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jaweriaparacha:
dear so that answer is 5.3 .
yo
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since molarity (M) =
no. of moles of solute / volume of solution in litres
mass of glucose ÷ molar mass of glucose / 0.300L
16 g÷180.156 g / 0.300 L
0.09 mol / 0.300
= 0.3 M
no. of moles of solute / volume of solution in litres
mass of glucose ÷ molar mass of glucose / 0.300L
16 g÷180.156 g / 0.300 L
0.09 mol / 0.300
= 0.3 M
thank u so much dear did u know that u solve my big problem thank u once again dear
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