Calculate molarity of solution containing 16 gram glucose per 300 ml solution
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Moles of glucose = Weight / GMW
= 16 / 18
= 8/9 mol
Molarity = Moles / Volume in litres
= (8/9) / (300 × 10^-3)
= 2.96 M
Molarity of solution is 2.96 M
= 16 / 18
= 8/9 mol
Molarity = Moles / Volume in litres
= (8/9) / (300 × 10^-3)
= 2.96 M
Molarity of solution is 2.96 M
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