Question

Calculate molarity of solution containing 9.8 g of sulphuric acid by mass dissolved per litre of the solution

Answer 1

Moles of solute = Mass of solute / Molar mass of solute

= 9.8 g / 98 g/mol

= 0.1 mol

Volume of solution = 25 cm³ = 0.025 Litres

Molarity = Moles of solutes / Volume of solution in litres

= 0.1 mol / 0.025 litres

= 4 M

Molarity of given solution is 4 M

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