Calculate molarity of solution of cacl2 if on chemical analysis it is found that 200 ml of cacl2 contains 3.01 into 10 to the power 22 cl negative ions
Answers
Answered by
75
Since CaCl2 has 2 chloride ions, the number of CaCl2 “molecules” in 200mL is
= 3.01x10^22 ÷ 2
= 3.01x10^22 ÷ 2 x 5 per litre
= 7.525 x 10^22 “molecules”
1 mole of a substance contains 6.02 x 10^23 “molecules”
Therefore, number of “molecules” of CaCl2 / litre
= 7.525 x 10^22 ÷ 6.02 x 10^23
= 0.125
CaCl2 solution is 0.125 M
HOPE IT WILL HELP YOU 。^‿^。。^‿^。
= 3.01x10^22 ÷ 2
= 3.01x10^22 ÷ 2 x 5 per litre
= 7.525 x 10^22 “molecules”
1 mole of a substance contains 6.02 x 10^23 “molecules”
Therefore, number of “molecules” of CaCl2 / litre
= 7.525 x 10^22 ÷ 6.02 x 10^23
= 0.125
CaCl2 solution is 0.125 M
HOPE IT WILL HELP YOU 。^‿^。。^‿^。
Answered by
16
Answer: 0.125M is the answer
Explanation:
CaCl2 has 2 chloride ions = 3.01 X 10^22/2
converting 200ml = 1/5L
=3.01 X 10^22/2 X 5
=7.5 X 10^22 molecules
now, number of molecules of CaCl2
= 7.525 X 10^22/6.02X10^23 (as, 1 mole contains 6.023X10^23 molecules)
= 0.125M
Molarity of CaCl2 solution is 0.125M
Hope it helps!
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