calculate molarity of the 10%hno3 (aq) solution having density 1.02g cc
Answers
We have to calculate the molarity of the 10 % HNO₃ of aqueous solution having density 1.02 g/cc
solution : 10% HNO₃ in a aqueous solution.
it means, a 100g of aqueous solution contains 10g of HNO₃.
now volume of solution = mass of solution/density of solution
= 100g/(1.02g/cc)
= 98.039 cc
no of moles of HNO₃ = given mass/molecular mass = 10g/(1 + 14 + 48) = 10/63 = 0.1587
so, molarity = no of moles of HNO₃ × 1000/volume of solution in mL
= 0.1587 × 1000/98.039
= 158.7/98.039
= 1.6187 ≈ 1.62 M
Therefore the molarity of the solution is 1.62 M
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