Question

Calculate
molarity of
the 10%
HNO3(aq) solution having
density
1.02g /
cc​

Answer 1

molarity= moles of HNO3 /litres of solution

Assuming, 1 litre of solution has been used.

Concentration of solution of HNO3 is 10%.

So, (10/100)* 1000 ml is HNO3, (90/100)*1000 ml

100 ml of pure HNO3 is used, 900 ml of pure distilled water is used.

ρ=1.02 g/cc

ρ=m/v  

1.02=m/100

m=102 g of HNO3 is used.

R.M.M of HNO3 is 1+14+3*16 =>15+48 => 63 g mol-1

So, 1 mol of HNO3 weighs 63 grams.

So, 102 g of HNO3 is 102/63 mol

1.619 mol.

molarity=1.619 mol/ (1 litre of solution)

molarity=1.62 M (approx.)