Question

calculate mole fraction molality and molarity of ethanol solution which is 50% by weight of ethanol in water and has density of 0.9144g/cc​

Answer 1

Explanation:

Everything in the attachment.

I expect u know the formulas

Hope it helps dear.

Answer 2

$\large\underline\mathrm\red{Given:-}$

• $\large\mathrm{Mole</li></ul><p>\: fraction \: of \: Ethanol \: = \: 0.05 }$
  • $\large\mathrm{The \: density \: of \: solution \: = \: 0.997 g/cc.}$

  $\large\underline\mathrm\red{Solution}$

  $\large\mathrm{Mole \: fraction \: of \: C2H5OH \: = \: mole \: of \: C2H5OH \: / \: moles \: of \: C2H5OH \: + \: moles \: of \: H2O}$

  $\implies$ 0.05

  $\implies$ 5/100.

  $\large\mathrm{100 \: moles \: of \: solution \: contains \: 5 \: moles \: of \: C2H5OH}$

  $\large\mathrm{Weight \: of \: C2H5OH \: = \: moles \: × \: mol. \: Wt}$

  $\implies$ 5 × 46

  $\implies$ 230 g.

  $\large\mathrm{Weight \: of \: H2O }$

  $\implies$ 95 × 18

  $\implies$ 1710 g.

  $\large\mathrm\red{Volume \: of \: solution:}$

  $\implies$ 1940/0.997 cc

  $\implies$ 1945.8 ml

  $\implies$ 1.9458 litres.

  $\large\underline\mathrm\red{Molality:-}$

  $\implies$ 5/1710 × 1000

  $\implies$ 2.92 m.

  $\large\underline\mathrm\red{Molarity:-}$

  $\implies$ 5/1.9458

  $\implies$ 2.57 M.

  ______________________________________