Question

Calculate mole fraction of an NaOH solution is prepared by dissolving 4 gram in 270 gram of water.​

Answer 1

Answer:

Mole fraction of H2O

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 moles

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 molesNo. of moles NaOH = 4/40 = 0.1 mol

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952Mole fraction of NaOH = 0.1/2.1 = 0.048

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952Mole fraction of NaOH = 0.1/2.1 = 0.048Mass of solution

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952Mole fraction of NaOH = 0.1/2.1 = 0.048Mass of solution= Mass of H2O + Mass of NaOH = 36 + 4 = 40 g

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952Mole fraction of NaOH = 0.1/2.1 = 0.048Mass of solution= Mass of H2O + Mass of NaOH = 36 + 4 = 40 gVolume of solution = 40/1 = 40 mL

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952Mole fraction of NaOH = 0.1/2.1 = 0.048Mass of solution= Mass of H2O + Mass of NaOH = 36 + 4 = 40 gVolume of solution = 40/1 = 40 mLMolarity = No.of moles of solute/Volume of solution in L

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952Mole fraction of NaOH = 0.1/2.1 = 0.048Mass of solution= Mass of H2O + Mass of NaOH = 36 + 4 = 40 gVolume of solution = 40/1 = 40 mLMolarity = No.of moles of solute/Volume of solution in L= 0.1/0.04L = 2.5M

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 36/18 = 2 molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952Mole fraction of NaOH = 0.1/2.1 = 0.048Mass of solution= Mass of H2O + Mass of NaOH = 36 + 4 = 40 gVolume of solution = 40/1 = 40 mLMolarity = No.of moles of solute/Volume of solution in L= 0.1/0.04L = 2.5M