Question

calculate mole fraction of HCL in a solution containing 24.8 % of HCL by mass​

Answer 1

Answer:

0.14

Explanation:

In 100 g of solution

Mass of HCl = 24.8 g

Moles of HCl = (24.8 g)/(36.5 g/mol) = 0.679 mol

Mass of water = (100 - 24.8) g = 75.2 g

Moles of water =  (75.2 g)/(18 g/mol) = 4.178 mol

Total mole = 0.679 mol + 4.178 mol = 4.857 mol

Mole fraction of HCl = (0.679 mol)/(4.857 mol) = 0.14