calculate mole fraction of HCL in a solution containing 24.8 % of HCL by mass
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Hey dude your answer is!!!!!!
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mole fraction = (moles of solute)/(moles of solute + moles of solvent)
So, we have to always assume (unless otherwise stated) that we have 100g of total mass. This means that we have 24.8g of HCl. On mol of HCl is 36.45g. So to find moles, we take 24.8/36.45 which gives us .68 moles of HCl. Now, 100-24.8 will give us how much water we have. Since we have 75.2 grams of water, we can now find the total moles of water. 75.2/18(Weight of one mol of water)=4.18 moles.
Back to our original equation..
(.68)/(.68+4.18)= about .14.
Hope this helps you plzz mark as brainliest
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mole fraction = (moles of solute)/(moles of solute + moles of solvent)
So, we have to always assume (unless otherwise stated) that we have 100g of total mass. This means that we have 24.8g of HCl. On mol of HCl is 36.45g. So to find moles, we take 24.8/36.45 which gives us .68 moles of HCl. Now, 100-24.8 will give us how much water we have. Since we have 75.2 grams of water, we can now find the total moles of water. 75.2/18(Weight of one mol of water)=4.18 moles.
Back to our original equation..
(.68)/(.68+4.18)= about .14.
Hope this helps you plzz mark as brainliest
lavanshukhadatkar:
answer is correct n
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