Question

Calculate mole fraction of hcl in solution of hcl containing 24.8 of hcl by mass

Answer 1

Answer:

HCl is 24.8% by mass solution..... ie. 24.8 g HCl in 100 g of water.

So, mass of HCl= 24.8g and mass of water = 100-24.8 = 75.2 g.

 Molar masses are -   HCl = 36.5 g/mol  and water - 18 g/mol

Therefore, no. of  moles of HCl = ( mass of HCl ) /  molar mass of HCl = 24.8/36.5 =  0.68 moles

                  no. of  moles of water = ( mass of water ) / molar mass of water = 75.2 / 18 = 4.18 moles

Hence mole fraction of HCl =  (no. of moles of HCl ) / total no of moles of HCl and water

                                              =  (0.68) / (0.68+4.18) = (0.68) / (4.86)

                                             =  0.139

Hence , mole fraction of HCl in the given solution is 0.139.

Answer 2

$\huge \underline \orange{Solution:}$

$\red{\text{Given:}}$

➡Mass of solute (Hcl) = 24.8g.

➡Mass of solution = 100g.

➡Mass of solvent = 100 - 24.8

= 75.2g

➡nHcl = 24.8/36.5

= 0.6795

= 0.68

➡nH2O = 75.2/18

= 4.4178

= 4.42

➡ xHcl = nHcl/nHcl + nH2O

= 0.68/0.68 + 4.42

= 0.68/5.10

= 68 × 10^-2/5.1

= 1.333 × 10^-1 × 10^-2

= 1.33 × 10^-1

= 0.133

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