Question

calculate mole fraction of water and NaCL when 40g of NaCL is dissolved in 360g of water ​

Answer 1

here is ur answer

Mole fraction of H2O

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)

Mole fraction of H2O= No.of moles of H2O/Total No.of moles (H2O + NaOH)No. of moles of H2O = 360/18 = 20moles

molesNo. of moles NaOH = 4/40 = 0.1 mol

molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1

molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952

molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952Mole fraction of NaOH = 0.1/2.1 = 0.048

molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952Mole fraction of NaOH = 0.1/2.1 = 0.048Mass of solution

molesNo. of moles NaOH = 4/40 = 0.1 molTotal number of moles = 2+0.1 = 2.1Mole fraction of H2O = 2/2.1 = 0.952Mole fraction of NaOH = 0.1/2.1 = 0.048Mass of solution= Mass of H2O + Mass of NaOH = 360 + 4 =

400g

gVolume of solution = 400/1 = 400 mL

mLMolarity = No.of moles of solute/Volume of solution in L

mLMolarity = No.of moles of solute/Volume of solution in L= 0.1/0.04L = 2.5M