Question

Calculate mole fraction of water and sulphuric acid in 49g of H2SO4 in 180 gram of water?​

Answer 1

Answer:

Explanation:

98 % of H2SO4 that means 98 g of H2SO4 is there in 100 g of aq. H2SO4 solution.

So.

Mass of solute = 98 g

Mass of solvent = 2 g (as water is considered as universal solvent)

Molar mass of solute = 98 g

Molar mass of solvent = 18 g

No of moles of solute = 1 mole (no of moles = given mass / molar mass)

No of moles of solvent = 2/18 = 1/9 moles

And ,

We know formula for mole fraction is..

x( of solute) = Moles of solute/(moles of solute + moles of solvent)

x (of solute) = 1/(1+(1/9)) = 0.9

x (of solvent) = 1 - 0.9 = 0.1

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