Question

Calculate mole fraction of water in a mixture of 12 g of water 108 g of acetic acid and 92 g of ethyl alcohol

Answer 1

Answer:

Explanation:

moles of water in mixture=12/18=2/3

moles of acetic acid in mixture = 108/60 = 18/10

moles of ethanol in mixture= 92/46 = 2

mole fraction of water = (2/3)/(2/3+1.8+2) = (2/3)/[(2+5.4+6)/3] =2/13.4=20/134 = 10/67

therefore 10/67 is the mole fraction of water in mixture.

hope this helps:p

Read more on Brainly.in - https://brainly.in/question/1161291#readmore