Question

Calculate mole of :
68g of NH3.
11.2 L of NH3.
3.0*(10)18.

Answer 1

Answer:

68g of NH3 = 4moles

11.2 L of NH3 = 0.5 moles

Explanation:

Number of moles= Given mass÷ molecular mass

Atomic mass of hydrogen =1

Atomic mass of nitrogen =14

Molecular mass of NH3= atomic mass of nitogen + 3×atomic mass of hydrogen

                                       =14+3

                                        =17g

Number of moles= 68÷17

                             =4moles

Number of moles of NH3= 4 moles

Now considering 11.2L of  NH3 , 22.4L occupies 1 mole , therfore 11.2L occupies 0.5 moles

Number of moles of NH3 = 0.5 moles