Question

Calculate mole of
O2 formed by decomposition
of 5 mol kClo3 . Also calculate mol of Al
required which completely react with produced O2 ​

Answer 1

Answer:

Very ez stoichiometric problem ;

1 - Answer is 7.5 moles

2- 4 moles of Al.

Explanation:

1 - We can see in image(1) that 2 moles of KClO3 is required to form 3 moles of oxygen gas.

So , by simple unitary method ,

2 moles of KClO3 ---> 3 moles of oxygen gas

1 mole of KClO3 -----> 3/ 2 moles of oxygen gas

5 moles of KClO3 -----> ( 3 / 2 ) × 5 moles of oxygen gas.

=> 15 / 2 moles = 7.5 moles.

2-

Produced Oxygen = 3 moles of oxygen gas( Given in 1st part).

We can see cleary in image (2) in first equation that there is be 6 oxygen in L.H.S. , so by law of conservation of mass , there must be 6 oxygen on R.H.S. But there are three oxygens , so we need to multiply it by 2 in order to follow law of conservation of mass.

So , ( 1 / 2 ) × X = 2

X = 4 .

Hence , 4 moles of aluminium is required to react with priduced oxygen.

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