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Calculate | molecular | formula assuming | that | whole of the hydrogen is present as Water of Crystallization |
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hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322 [Na = 23, ...
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mole of Na = 14.31/23 = 0.622mole of S = 9.97/32 = 0.311mole of H = 6.22/1 = 6.22mole of O = ... More
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Na+S+O=14.31+9.97+69.5=93.78rest part is H100-93.78=6.22•/•Na=14.31/23 = 0.622 = 0.622/0.311= ... More
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hope this helps you mate xD
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