Question

Calculate molecular mass of following :i) CaCO3 ii) HNO3 iii) C12H22O11 iv) MgSO4.7H2O

Answer 1

Answer:

i) 100.0869 g/mol

ii) 63.01 g/mol

iii) 342.3 g/mol

iv) 120.366 g/mol

Answer 2

Answer:

I)CaCO3- 1×40+1×12+3×16

=100u

(Mass of Ca=40, C=12 ,O=16)

ii)HNO3 -1×1+1×14+3×16

=63u

(Mass of H=1,N =14,O=16)

iii)C12H22O11-12×12+1×22+16×11

=144+22+177

=342

(Mass of C=12 H=1 O=16)

iv)MgSO4.7H2O-24+32+4×16+7(2×1+16)

=24+32+64+126

=246