Question

Calculate molecular mass1.Mg3N2 2.(NH2)2CO 3.(NH4)2CO3 where Na=24,H=1,O=16,C=12,N=14,Mg=24​

Answer 1

Answer:

1.

Mg3N2

24×3 + 14×2

= 72+28

= 100 a.m.u.

2.

(NH2 )2 CO3

14×2 + 4×1 + 12+16×3

= 28+4+12+48

= 92 a.m.u

3.

(NH4)2CO3

2× 14 + 8×1 + 12+ 16× 3

= 28 + 8 + 12 + 48

= 96 a.m.u