Question

calculate molecular weight caco3​

Answer 1

CaCO3

= 40 × 1+ 14×1+3×16

=40+14+48

=92 g.

therefore the molecular weight of CaCO3 is 92 g.

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Answer 2

Answer:

Given compound: CaCO3

$atomic \: weight \: of \: calcium = 40$

$atomic \: weight \: of \: carbon = 12$

$atomic \: weight \: of \: oxygen = 16$

as there are. three oxygens so 3×16=48

Total mass=

$40 + 12 + 48 = 100amu$

The mass of compound is 100amu