Question

Calculate molecular weights of the following compounds?
(At. Wt. of N=14, O=16, S=32, H=1, Na=23, C=12).
(i) NO2
(ii) SOZ
(iii) H2SO4
(iv) CO₂
(v) NaOH​

Answer 1

Explanation:

1.14+2*16=46

2.32+2*16=64

3.2+32+64=98

4.12+2*16=44

5.24+16+1=41

Answer 2

Answer:

Explanation:

NO2 ---- 14 + 2×16 = 46 g/mol

SO2 --- 32 + 2×16 = 64 g/mol

H2SO4 ---- 2×1 + 32 + 4×16 = 98g/mol

CO2 ----- 12 + 2×16= 44g/mol

NaOH --- 23+ 16 + 1 = 40 g/mol