Question

calculate molefraction of HCl in its 36.5 percent solution​

Answer 1

Answer:

So, mass of HCl= 24.8g and mass of water = 100-24.8 = 75.2 g.

Molar masses are -   HCl = 36.5 g/mol  and water - 18 g/mol

Therefore, no. of  moles of HCl = ( mass of HCl ) /  molar mass of HCl = 24.8/36.5 =  0.68 moles

                 no. of  moles of water = ( mass of water ) / molar mass of water = 75.2 / 18 = 4.18 moles

Hence mole fraction of HCl =  (no. of moles of HCl ) / total no of moles of HCl and water

                                             =  (0.68) / (0.68+4.18) = (0.68) / (4.86)

                                            =  0.139

Hence , mole fraction of HCl in the given solution is 0.139.